Momentum in special relativity problem

In summary, the conversation discusses finding momentum and the energy-momentum relationship. The question posed is about the correct method for finding momentum, to which the response is to use the energy-momentum relationship. The conversation also touches on the concept of a "right way" to find momentum and discusses the solution shown in the accompanying picture. The expert summarizes the main points of the conversation and clarifies the topic of finding momentum.
  • #1
sapz
33
1

Homework Statement


Hi there.

I added a question as an image, what is the right way to find the momentum?

Homework Equations





The Attempt at a Solution

 

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  • #2
what is the right way to find the momentum?
You use the energy-momentum relationship.

##E^2 = m^2c^4 + p^2c^2##

The kinetc energy is ##K=(\gamma -1)mc^2## and ##E=\gamma mc^2##
 
  • #3
Im aware of that. However could you please address the question in the picture? Which way is wrong, and why?
 
  • #4
I was[/] addressing the pic.
The pic includes the question "What is the momentum of the moving particle?"
You wanted to know the right way to go about it - I told you.

It seems I misunderstood.
Define "right way". (What makes you think there is a wrong way in there?)
The pic shows you how to solve for two contexts in relation to the center-of-mass.
 
Last edited:
  • #5


In special relativity, momentum is defined as the product of an object's mass and its velocity. This can be expressed mathematically as p = mv, where p is the momentum, m is the mass, and v is the velocity. However, in order to properly calculate momentum in special relativity, we must also take into account the effects of time dilation and length contraction. This can be done using the Lorentz transformation equations.

To find the momentum of an object in a specific reference frame, we must first determine the object's velocity in that frame. This can be done by using the Lorentz transformation formula for velocity, v' = (v + u)/(1 + (vu/c^2)), where v' is the velocity in the new frame, v is the velocity in the original frame, u is the relative velocity between the two frames, and c is the speed of light.

Once we have the velocity in the new frame, we can then use the equation p = mv to calculate the momentum. It is important to note that in special relativity, momentum is a relativistic quantity and is not conserved in all reference frames. Therefore, it is essential to use the correct equations and transformations when calculating momentum in special relativity problems.
 

1. What is momentum in special relativity?

Momentum in special relativity is a measure of the motion of a particle or system of particles. It takes into account both the mass and velocity of the particles, and is a fundamental concept in understanding the behavior of objects at high speeds.

2. How is momentum different in special relativity compared to classical mechanics?

In classical mechanics, momentum is defined as the product of mass and velocity. However, in special relativity, momentum is defined as the product of the relativistic mass and the velocity, where the relativistic mass takes into account the effects of high speeds on an object's mass.

3. What is the equation for calculating momentum in special relativity?

The equation for calculating momentum in special relativity is p = m * v / √(1 - v2/c2), where p is momentum, m is mass, v is velocity, and c is the speed of light.

4. How is momentum conserved in special relativity?

In special relativity, momentum is conserved in the same way as in classical mechanics. This means that the total momentum of a closed system remains constant, even when the system is experiencing high speeds or undergoing relativistic effects.

5. What are some real-world applications of momentum in special relativity?

Momentum in special relativity has important applications in fields such as particle physics, astrophysics, and nuclear energy. It is also essential in understanding the behavior of high-speed objects and the effects of extreme speeds on their mass and energy.

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