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Momentum of a Ball

  1. Nov 11, 2011 #1
    1. The problem statement, all variables and given/known data
    An 80 kg man standing at rest on a smooth, level ice surface throws a 200g ball horizontally with a speed of 25 m/s, relative to the Earth. a) With what speed and in what direction does the man move? b) If the man throws six such balls every 5.0s, what is the average force acting on him?


    2. Relevant equations
    Ft=mv


    3. The attempt at a solution
    I got part a using the conservation of momentum equation, but I don't get how to do b.
    Can anyone help?
     
  2. jcsd
  3. Nov 11, 2011 #2

    Delphi51

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    Use F = ma = M*Δv/Δt
    Every throw gives him a bit of Δv. Multiply it by 6 for 6 throws.
     
  4. Nov 12, 2011 #3
    Okay, I got it. Thanks!
     
  5. Nov 12, 2011 #4

    Delphi51

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    Most welcome!
     
  6. Nov 12, 2011 #5
    Force = rate of change of momentum
    Force = change in momentum per second
    Force = change in momentum of each interaction x number of interactions per second
    This is another way to say what Delphi51 said.
     
  7. Nov 12, 2011 #6
    Okay thanks!
     
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