A 7.45g bullet has vi = 353 m/s. It strikes the 0.725 block of a ballistic pendulum and passes completely through the block. If the block rises through a distance h = 12.1 cm, what was the velocity of the bullet as it emerged from the block?
Energy conservation and momentum
The Attempt at a Solution
First I solved for the velocity of the block when the bullet hit it. I used conservation of energy 1/2mv2 = mgh. I got the velocity as 2.41 m/s. Then I used conservation of momentum.
.00745(353)=.725(2.41) + .00745vf.
I solved for vf and got 118.5 m/s. The answer is supposed to be 203 m/s. I have tried combining the masses with the 2.41 velocity, but it still doesn't work out.
Can some one help me out? Thanks.