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Momentum on a pool table

  1. Nov 27, 2011 #1
    When ball 1 hits ball 2, they both go off at different angles. What is the final velocity of the second ball?

    ball 1=4 kg
    ball 2= 10 kg
    Vo1=8 m/s
    Vf1=3 m/s
    θ=34 ° (ball 2 moves at a speed of 3 m/s @ 34°)
    Solve for Vf2 and the angle for ball 2 after the collision (Angle β)

    Relevant equations:
    m1vo1 + m2vo2 = m1vf1 + m2vf2

    i did (4)(8) + 0 = (10)(vf2)

    i had no clue if this was right though. are you supposed to use sin, cos, or tan θ?
  2. jcsd
  3. Nov 27, 2011 #2


    User Avatar

    Staff: Mentor

    But you just said that ball 2 moves at a speed of 3 m/s @ 34° :confused:
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