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Momentum Operator Proof

  • Thread starter csutton1
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Does anyone have a momentum operator proof? The book I'm using is skipping a lot of steps .
 

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siddharth
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Could you be more specific? Proof of what?
 
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sorry i re-read my post and realized it was really vague. The momentum operator used to determine the momentum of a particle described by schrodingers wave equation.
 
siddharth
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sorry i re-read my post and realized it was really vague. The momentum operator used to determine the momentum of a particle described by schrodingers wave equation.
Yes, what about it? I don't understand what proof you have in mind. Maybe, if you post the exact problem statement, and where you are stuck, it'll be easier to help.
 
malawi_glenn
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I am also stunned, are you saying that you want a proof that

[tex] -i\hbar \nabla [/tex]

gives the momentum of a state?

Be specific, and write down for us where you get stucked.
 
JK423
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There is no *proof*, but there is a "classical" way to calculate it. But still it`s not a *proof*.
Assume that this relation for the mean values is valid:
<P>=m*d<x>/dt.
Then substitute <x>=(Ψ,xΨ), do the math and you`ll get the well known result:
<P>=(Ψ,pΨ), where p is the momentum`s operator.
 
malawi_glenn
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No JK423, that is not what you do. You want to show that the p operator is the generator of translations and that it fulfills certain commutation relations.
 
JK423
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No JK423, that is not what you do. You want to show that the p operator is the generator of translations and that it fulfills certain commutation relations.
I mentioned a way to calculate momentum`s operator in {x} representation from a known classical equation. What`s wrong about that?
What do you mean by
"You want to show that the p operator is the generator of translations and that it fulfills certain commutation relations" ?
You can show these these things without knowing what operator p equals to?
 
malawi_glenn
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Well what you wrote is ok :-)
but is not a proof, as you said.



but I know what p equals, so I can proove that it is the generator of translation and fulfills certain commutator relations. I did not say that i was about to derive the momentum operator, which is done by doing the steps backwards. I.e I demand translations symmetry and that it fulfills certain commutator relations.

It is quite simple.
 

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