A Skateboarder with mass m1=48kg runs at 6.8m/s and jumps onto her skateboard with mass m2=2.9kg which is at rest at the bottom of a curved ramp. When the skateboarder lands on the board, how high does she and the skateboard go?(adsbygoogle = window.adsbygoogle || []).push({});

Relevant equations

w=[1/2(MVf^s)-1/2(MVi^2)]+[(MGHf-MGHi)]

The attempt at a solution

[(1/2(50.9)(0)^2)-(1/2(50.9)(6.8)^2)]+[(50.9)(9.8)(x)-(50.9)(9.8)(0)]

I found this to work out to

(0-1176.81)+(498.82x-0)

x=2.36m

I have worked out his equation and found Hf to be 2.36m im just not sure if this is correct or if not could someone enlighten me on another equation or where i went wrong thanks.

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# Homework Help: Momentum problem

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