Momentum problem

  • Thread starter Lacnez
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  • #26
haruspex
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The horizontal before the split was 0 cause it was going vertical

For one of the pieces I did now

P=mv
(0.5)(25)
=12.5

Then
12.5sin7.5

I get as a horizontal 1.6315
Good. Stop there. You have answered the question.
Then subtract

1.6315-(-1.6315) = 3.263
 
  • #27
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so the answer to my question of change in momentum would be the 3.263
 
  • #28
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The sine is not the right trigonometric function...
The right function will give a similar, but not the same result.

so the answer to my question of change in momentum would be the 3.263
No, see haruspex' post. The change for each piece is from 0 to [value close to 1.6 kg m/s], and that value close to 1.6 is the right answer.
 
  • #29
haruspex
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so the answer to my question of change in momentum would be the 3.263
No, I said "stop there" after you wrote
horizontal 1.6315
You should add the units, but otherwise that's it: the magnitude and direction of the change in momentum of each part (but they will have opposite signs, of course).
 
  • #30
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ok so i leave it as is at 1.6315 or do i add 1.6315 + 1.6315 to get the final answer
 
  • #31
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Don't add.

There is a different problem:
The sine is not the right trigonometric function...
The right function will give a similar, but not the same result.
 
  • #32
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alright i did 12.5tan7.5 = 1.6457 kg m/s
 
  • #33
haruspex
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alright i did 12.5tan7.5 = 1.6457 kg m/s
Yes (Good catch mfb.) But you need all three items in the answer: the direction, the numerical magnitude and the units. If you omit any of those it could be marked wrong.
 
  • #34
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alright thanks a lot guy I apologize for the inconvenience I'm doing this course all online and no one to help or teach it to me so it's not the greatest thing.

Thanks again
 

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