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(a) So [tex] p = mv [/tex]. That means [tex] (0.4 kg)(12.0 \frac{m}{s}) = (80.4 kg)(v) [/tex] and you just solve for [tex] v [/tex]?

(b) Would you do: [tex] (0.4 kg)(11.0 \frac{m}{s}) = (80.0 kg)(v) [/tex] and solve for [tex] v [/tex]?

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(a) So [tex] (0.500 m/s)(3.00 kg) = (1.00 kg)(v) [/tex] and you just solve for [tex] v [/tex]?

(b) The potential energy of a spring is [tex] \frac{1}{2}kx^{2} [/tex]. How would you find [tex] k [/tex] and [tex] x [/tex]?

Thanks

**1**) You are standing on a sheet of ice that covers a parking lot; there is negligible friction between your feet and the ice. A friend throws you a 0.400 kg ball that is traveling horizontally at 12.0 m/s. Your mass is 80.0 kg. (a) If you catch the ball, with what speed do you and the ball move afterward? (b) If the ball hits you and bounces off your chest, so that afterward it is moving horizontally at 11.0 m/s in the opposite direction, what is your speed after the collision?(a) So [tex] p = mv [/tex]. That means [tex] (0.4 kg)(12.0 \frac{m}{s}) = (80.4 kg)(v) [/tex] and you just solve for [tex] v [/tex]?

(b) Would you do: [tex] (0.4 kg)(11.0 \frac{m}{s}) = (80.0 kg)(v) [/tex] and solve for [tex] v [/tex]?

(

**2**) Two blocks are forced together, compressing a spring in between them. The first block has a mass of 1.00 kg, and the second block has a mass of 3.00 kg. The spring is not fastened to either block and drops to the surface after it has expanded. Block B acquires a speed of 0.5 m/s. (a) What is the final speed of Block A? (b) How much potential energy was stored in the compressed spring?(a) So [tex] (0.500 m/s)(3.00 kg) = (1.00 kg)(v) [/tex] and you just solve for [tex] v [/tex]?

(b) The potential energy of a spring is [tex] \frac{1}{2}kx^{2} [/tex]. How would you find [tex] k [/tex] and [tex] x [/tex]?

Thanks

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