1. The problem statement, all variables and given/known data 2. Relevant equations Mg deltha H 1/2mv^2 p=mv 3. The attempt at a solution I believe statement to do with the Gravitational energy is correct, considering the equation I listed. I would have to agree with statement 2 since gpe=ke Here is what I am thinking, I disagree with the Ke = the same as before collision. my reason is 1/2mv^2= 0.16j ----- v= sqrt (0.32/71.6ex-3) now if this is correct we can work out the momentum which i have down as 1.5 x10^-1 using, momentum is conserved we can work out velocity of the pellet which turns out to be 180m/s (I think this could be wrong) But could I just say that, the collision was inelastic, hence kinetic energy is not conserved, therefore working out velocity from Momentum would be better since momentum is conserved.