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Monkey friction

  1. Aug 30, 2007 #1
    1. The problem statement, all variables and given/known data

    A box of bananas weighing 40.0N rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.40 and the coefficient of kinetic friction is 0.20.

    a) If no horizontal force is applied to the box and the box is at rest, how large is the friction force exerted on the box?

    b) What is the magnitude of the friction force if a monkey applies a horizontal force of 6.0N to the box and the box is initially at rest?

    c) What minimum horizontal force must the monkey apply to start the box in motion?

    d) What minimum horizontal force must the monkey apply to keep the box moving at constant velocity once it has been started?

    e) If the monkey applies a horizontal force of 18.0N, what is the magnitude of the friction force ?

    f) If the monkey applies a horizontal force of 18.0N, what is the box's acceleration?


    2. Relevant equations

    F=ma

    3. The attempt at a solution

    a) if there is no force applied to the box, the friction force exerted is 0N? or would i times the coefficients of both static and kinetic energy with the weight of the box?

    b) just the 6N applied? or the (static friction coefficient x weight) - 6N?

    c) 40N x coefficient of static = 16N

    d) 40N x coeff of kinetic = 8N

    e) remains 8N

    f) having a major mind blank over this one.

    so yeh, just needing some pointers for parts a, b and f.
    thanks in advance.
     
  2. jcsd
  3. Aug 30, 2007 #2
    just got part b correct, only need help with part a and f thanks.
     
  4. Aug 30, 2007 #3

    learningphysics

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    Homework Helper

    For a you're right, there is 0 frictional force.

    For f... what is the net force acting in the horizontal direction while the box is moving? Use this and F=ma to get the acceleration.
     
  5. Aug 30, 2007 #4
    18N to the right, minus 8N to the left (kinetic friction x weight) = 10N to the right.

    F=ma
    10=40a
    a=0.25m/s?

    or am i using the wrong value for m?
     
  6. Aug 30, 2007 #5

    learningphysics

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    The m is wrong. 40N is the weight not the mass. Get the mass from W = mg.
     
  7. Aug 30, 2007 #6
    once again on my final submission :p, so could you please just verify this is correct for me>

    F=ma
    10=4.08a
    a=2.45m/s

    thanks
     
  8. Aug 30, 2007 #7

    learningphysics

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    Yup, only the units are wrong. :wink: 2.45m/s^2
     
  9. Aug 30, 2007 #8
    sweet thanks :)
     
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