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Monotonius function

  1. Mar 19, 2008 #1
    Why there is only one solution of the monotonous functions, when all of the functions all monotonous?

    For example, I read that this example is monotonius function and because of that have only one solution

    [tex]5^x + 7^x=12^x[/tex]

    x=1


    btw- how to solve monotonius functions?
     
  2. jcsd
  3. Mar 20, 2008 #2

    HallsofIvy

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    In English that would be "monotonic". What do you mean by "all of the functions are monotonic? And my problem is not with your saying that [tex]5^x + 7^x=12^x[/tex] is monotonic but that it is a function at all! That is an equation. Perhaps you are confusing "function" with "equation" but in that case, I don't recognise the phrase "monotonic equation".

    In any case, the definition of "monotonic" is that if f(x)= f(y) then x= y. You cannot have two different values of the independent variable giving the same value of the dependent variable.

    That means, in particular, that if f(x) is a monotonic function then the equation f(x)= a, for any a, cannot have more than one solution- it has either no solutions or one.

    There is no general method for solving equations involving monotonic functions. Many polynomial functions, of odd degree, are monontonic but there is no general method of solving them.
     
    Last edited: Mar 20, 2008
  4. Mar 20, 2008 #3
    Yes, you are tottally right. I mistranslated all the things, and you are reading my mind... I was supposed to say, that every function is either monotonically increasing or monotonically decreasing. What is the difference between the functions [tex]\frac{5^x}{12^x}[/tex], [tex]\frac{7^x}{12^x}[/tex] and some other function like [tex]5^2^x=5^1[/tex]
     
  5. Mar 21, 2008 #4

    HallsofIvy

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    [itex]f(x)= \frac{5^x}{12^x}= \left(\frac{5}{12}\right)^x[/itex] and [itex]g(x)= \frac{7x}{12^x}= \left(\frac{7}{12}\right)^x[/itex] are functions. It would make no sense to say "solve for x" since x could be any number. The last, [itex]5^{2x}= 5[/itex] is an equation (the "=" between two different functions is a give-away!). It is only true if x= 1/2.
     
  6. Mar 21, 2008 #5
    I can't understand, why monotonic function have only one solution?
     
  7. Mar 22, 2008 #6
    but also [itex]f(x)=5^2^x[/itex] is monotonic function, so also [itex]5^x[/itex](lets say [itex]5^x[/itex] instead of 5) must bee monotonic function.

    [tex]5^2^x=5^x[/tex]
     
  8. Mar 22, 2008 #7
    Make it simpler, take [itex]f(x)=x[/itex] and [itex]f(x)=2x[/itex]. What about that? Should I dare to write [itex]x = 2x[/itex]?

    Are you looking for the intersection points of these functions? Because it seems like you are. Then, you can look for the unique arguments of these functions at the intersection points since they are monotonic.
     
  9. Mar 22, 2008 #8
    No, I can't understand why monotonic function have only one solution?
     
  10. Mar 22, 2008 #9

    HallsofIvy

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    If f(x)= f(y), which is larger, x or y?
     
  11. Mar 22, 2008 #10

    tiny-tim

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    Hi Physicsissuef! :smile:

    "monotonic increasing" means that, if x < y, then f(x) < f(y).

    So if f(a) = 0, then f(x) < 0 for all x < a, and f(x) > 0 for all x > a.

    In other words, a is the only value of x for which f(x) = 0. :smile:

    (If you draw a graph, isn't that obvious? :confused:)
     
  12. Mar 23, 2008 #11
    But isn't all function monotonic increasing, or monotonic decreasing?
     
  13. Mar 23, 2008 #12

    tiny-tim

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    Hi ! :smile:

    "monotonic increasing" means that, if x < y, then f(x) < f(y).

    "monotonic decreasing" means that, if x < y, then f(x) > f(y).

    In other words, the graph of a monotonic increasing function always goes up :biggrin: ,
    but the graph of a monotonic decreasing function always goes down :cry: .​

    "monotonic" doesn't mean single-valued (though the inverse of a monotonic function will be single-valued, over its range).
     
  14. Mar 23, 2008 #13
    then why everywhere that because of monotonic function it has only one solution?
     
  15. Mar 23, 2008 #14

    tiny-tim

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    Because, if y = f(x) is monotonic, it can only cross y = 0 once.

    So there is only one value of x for which y = 0. :smile:
     
  16. Mar 23, 2008 #15
    But it also have one value for x[tex]5^2^x-5^x=0[/tex]
     
  17. Mar 23, 2008 #16

    tiny-tim

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    I don't understand. :confused:

    Are you saying that 5^2^x - 5^x is monotonic increasing, but that 5^2^x - 5^x = 0 has more than one solution?
     
  18. Mar 23, 2008 #17
    Yes. Some functions are monotonic increasing or decreasing, but they have 2 or more solutions.
     
  19. Mar 23, 2008 #18

    tiny-tim

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    ok, what are the two solutions of 5^2^x - 5^x = 0?
     
  20. Mar 23, 2008 #19
    No, I am not talking about this function, I am talking about some function else, like:

    [tex]5^x+5^2^x-6=0[/tex]
     
  21. Mar 23, 2008 #20

    tiny-tim

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    ok, what are the two solutions of that?
     
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