A thin, uniform rod of length L = 0.850 m and mass M rotates horizontally about an axis through its center, at an angular velocity 18.5 rad/s. A particle with mass M/3.00 is attached to one end. The particle is then ejected from the rod by a small explosion. The explosion sends the particle along a path that is perpendicular to the rod at the instant of the explosion, with a speed that is 6.00 m/s greater than the speed of the end of the rod after the explosion. What is the speed of the ejected particle? I attempted to find the speed by solving for v in the following equation: [(1/12)ml^2]*(w) = (M/3)(v)(l/2) then i added 6. this gives me 8.62, which is wrong. Please tell me what I'm doing wrong! Thanks!