The way to solve this, i tried is by saying F = k(q1)(q2) / r^2. So, the force between the two charges is (9x10^9)(2.6x10^-8)(5.5x10^-8) / (1.4^2). Although, from there I'm not sure where to go because that just solves for the force inbetween the two charges and not the EPE or even more specifically the EPE midway between them.(1)Two charges of +2.60 x 10^-8 and -5.50 x 10^-8 C are separated by 1.40 m. What is the electric potential midway between them?
I started by saying that Electric Force = k(q1)(q2) / r^2,(2) Three charges are located at teh corners of a square whose sides are 2.0m in length. The charges are +2.0, +14, and +5.0 microCouloumbs. The empty corner of the square is opposite the +14 micro coloumb charge. How much work is required to bring up a fourth charge of +8microColoumbs and place it at the empty corner?
Then I figured I would apply that to all 3 charges with the +8charge as q2. Next I would add up all the three forces together to find the total amount of force needed. Except, theres where I get stuck, since that single equation can't be applied to all 3 charges seperately since - don't they all effect one charge?
Any help appreciated.