hi guys. got another question for ya. ........................................ seems to of uploaded small but i explain. a reservoir is designed to retain water to a max depth of 10metres. if the water level exceeds 10 metres, then a hinged semi circle gate will open to release any excess water. the gate has a radius of 1m. the gate is hinged 9 metres below the free surface. what would be the force required to open gate? what is the depth from the free surface to the the centre of pressure. ........................................ i know the second moment of area of a semi circular surface is 0.1102R4 but not sure how to complete the question. help with working out the answer would be much appraicated so i can work back on the answer and see how to get it. thanks adzp
In a general sense, you need to calculate the pressure distribution on the gate. From there, using the hinge location, you can use the area to calculate a force on the gate.
hi i have worked out the area and it is 1.571 once i have got the area of the gate, then how to i calculate the force required to open it? thanks adzp
the 2nd moment of area Ig about axis through centroid is 0.1102Rto the power of 4 so that would be 0.1102 x 1.571 to the power of 4 which is 0.272? still confused where to go next adzp