More Friction

  • Thread starter Izekid
  • Start date
  • #1
40
0
Here it comes, I have a frictiongrade who is 0,45 A car who is driving in 18m/s and mass of the car 1200kg

For the Frictionpower it is : 0,45 * (mg) = 5,5 kN

And how do I calculate the meters the car travels until it stops?
 

Answers and Replies

  • #2
36
1
initial kinetic energy - work done by friction = 0

(1/2)m(vo)^2 - f(delta x) = 0

solve for delta x
 
  • #3
andrevdh
Homework Helper
2,128
116
Use the work-kinetic energy theorem. That is the work done by all of the forces acting on an object (or the resultant of all of these) is equal to it's change in kinetic energy:
[tex]W_{F_R}=\Delta K[/tex]
 

Related Threads on More Friction

  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
6
Views
2K
  • Last Post
Replies
7
Views
2K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
0
Views
2K
  • Last Post
Replies
4
Views
5K
Replies
10
Views
560
Replies
11
Views
4K
Replies
2
Views
2K
Top