- #1

- 40

- 0

For the Frictionpower it is : 0,45 * (mg) = 5,5 kN

And how do I calculate the meters the car travels until it stops?

- Thread starter Izekid
- Start date

- #1

- 40

- 0

For the Frictionpower it is : 0,45 * (mg) = 5,5 kN

And how do I calculate the meters the car travels until it stops?

- #2

- 36

- 1

initial kinetic energy - work done by friction = 0

(1/2)m(vo)^2 - f(delta x) = 0

solve for delta x

(1/2)m(vo)^2 - f(delta x) = 0

solve for delta x

- #3

andrevdh

Homework Helper

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[tex]W_{F_R}=\Delta K[/tex]

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