(adsbygoogle = window.adsbygoogle || []).push({}); more kinetics :(

sigh heres another one i thought i knew how to do but i ended up with the wrong answer.

A brick is dropped from the roof of a building. Twenty meters below the point of release is the top of a window. How long will it take the brick to pass in front of the window which is 21.5 m tall?

d=21.5 m

a=9.8m/s

vi=0

t=?

i used d=vit+1/2a(t)^2 formula so..

21.5=0+1/2(9.8)(t)^2

did i do that right...

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# More kinetics

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