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## Homework Statement

Light of wavelength 680 nm falls on two slits and produces an interference pattern in which thefourth-order fringe is 38 mm from the central fringe on a screen 2.0 m away. What is the separationof the two slits?

## Homework Equations

Sin[tex]theta[/tex]=2m([tex]\lambda[/tex]2d)

x=L([tex]\lambda/d[/tex]

## The Attempt at a Solution

My givens are:

[tex]\lambda[/tex]= 680nm

L= 2.0m

x

_{4}38mm

using equation x=L([tex]\lambda/d[/tex] I got:

0.038 = 2.0m(680 x 10

^{-9}(4)/d)

d=2.0m(680 x 10

^{-9}(4)/d)/0.038)= 1.4x10

^{-4}m

Am I doing this correctly?

Thanks.