- #1

- 119

- 0

https://www.physicsforums.com/showthread.php?t=162079

Now I am having more troubles with more advanced problems.

I started with this problem:

[4y^2 - 7y - 12] / [(y)(y+2)(y-3)]

The problem is that I set it up the same way as I did in that thread and I am able to solve for A, B, and C:

A= 3

B= 9/5

C= 1/5

so I integrate 3/y + (9/5)/(y+2) + (1/5)/(y-3)

and i get

3ln(y) + 9/5ln(y+2) + 1/5ln(y-3)

Beautiful right? Well I am suppost to find the integral over the area from 1 to 2.

When I plug in 1 and 2 into the 1/5 ln (y-3) it yields a negetive number and you can't take the ln of a negetive number!

Im sure I am making the mistake in the polynomial division somewhere but i don't know. I am thinking there is a way to simplify the original question first before i solve for A B and C... right? any insite would be wonderful!