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More Spring oscillation

  1. May 18, 2008 #1
    [SOLVED] More Spring oscillation

    1. The problem statement, all variables and given/known data
    A 2.20 kg mass is attached to a spring and placed on a horizontal, smooth surface. A horizontal force of 17.6 N is required to hold the mass at rest when it is pulled 0.200 m from its equilibrium position (the origin of the x axis). The mass is now released from rest with an initial displacement of xi = 0.200 m, and it subsequently undergoes simple harmonic oscillations. Calculate the maximum speed of the mass.

    I've calculated the following already:
    Spring constant is 88.0 N/m
    Oscillation frequency is 1.00 Hz



    2. Relevant equations
    This is pretty much the problem; i dont know what equation to use to get the max velocity



    3. The attempt at a solution
    Ive been messing around with V = -AwSin(wt) but i cant fathom how to get amplitude..
     
  2. jcsd
  3. May 18, 2008 #2

    Hootenanny

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    HINT: The amplitude is given in the question.
     
  4. May 18, 2008 #3
    mkay, well the only thing i can see close to amplitude is Xi. But if thats amplitude, then all i have left to find is time..
     
  5. May 18, 2008 #4

    Hootenanny

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    xi is indeed the amplitude. However, there is no need to consider the amplitude, period, angular velocity etc. This problem can be trivially solved using conservation of energy.
     
  6. May 18, 2008 #5
    Ek = 1/2 mv^2, but i dont have kenetic energy...
     
  7. May 18, 2008 #6

    Hootenanny

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    No you don't have the kinetic energy, but you can work out the initial potential energy...
     
  8. May 18, 2008 #7
    Ep= 1/2 kX^2 <-- is this the equation you're referring to?
     
  9. May 18, 2008 #8

    Hootenanny

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    Indeed it is, and since energy is conserved you can use this to determine the velocity of the mass at any point.
     
  10. May 18, 2008 #9
    woohoo! Thanks for your help!
     
  11. May 18, 2008 #10

    Hootenanny

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    No problem :smile:

    Don't forget to mark the thread as 'solved' when your done.
     
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