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More Tangents

  1. Sep 30, 2007 #1
    Find an equation for the tangent to the curve y=1/(x-1) that has slope -1.
  2. jcsd
  3. Oct 1, 2007 #2
    Ok you have y, you know that y'=-1. Is there a way you can find a point x where this happens?
  4. Oct 1, 2007 #3


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    If y= 1/(x-1)= (x-1)-1, what is y'? (I hereby give you permission to use (xn)'= nxn-1!)
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