1. The problem statement, all variables and given/known data Show that the tangent to the curve [tex]y=(x^2+x-2)^2+3[/tex] at the point where x =1 is also tangent to the curve at another point. 2. Relevant equations [tex]y=(x^2+x-2)^2+3[/tex] 3. The attempt at a solution [tex]y'=2(x^2+x-2)(2x+1)[/tex] [tex]y'(1)=0[/tex] [tex]0=2(2x+1)(x+2)(x-1)[/tex] x= -1/2, -2, 1 Would this be correct?