# Motion and acceleration.

1. Sep 8, 2015

### Ashkon

1. The problem statement, all variables and given/known data
A skater moving on a frictionless ice at 8.0 m/s hits a 5.0-m-wide patch of rough ice. She slows steadly, the continues at 6.0 m/s. What is her acceleration on the rough Ice

2. Relevant equations
v2 = vo 2 + 2a (d-do)

3. The attempt at a solution
I have tried to set up the formula but I'm not sure how to do it properly.

a = vo 2 + 2v2 (d-do)

2. Sep 8, 2015

### andrewkirk

v and v0 are the final and initial velocities.
d and d0 are the distances from the skater's starting point to the end and beginning of the rough ice

3. Sep 8, 2015

### SteamKing

Staff Emeritus
Your algebra in transposing the Equation in 2.) to the Equation in 3 is a little dodgy.

You can't just switch the positions of a and v2 like you show.

4. Sep 8, 2015

### Ashkon

I understand that, I just have problems with setting up the formula.

5. Sep 8, 2015

### SteamKing

Staff Emeritus
Well, we can't do your algebra for you. You'll have to take the Equation in Section 2 and solve for a using standard algebraic rules.

6. Sep 8, 2015

Deleted

7. Sep 8, 2015

### SteamKing

Staff Emeritus
Do you or do you not understand algebra?

You've already tried switching a and v2, and we told you that wasn't correct.