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Motion, constant acceleration

  • Thread starter alexgraham
  • Start date
  • #1
A car slows down from 23 m/s to rest in a distance of 85m. what was its acceleration, assumed constant?



a=Δv/Δt x=1/2at^2



i don't know where to start
 

Answers and Replies

  • #2
2,967
5
what is the velocity-displacement formula?
 
  • #4
in that equation is v the change in velocity?
 
  • #5
66
0
Ignore this post, it was bad advice!
 
Last edited:
  • #7
okay thanks i guess my teacher messed up
 
  • #8
66
0
I'm sorry, I just gave you some bad advice...ignore my first response.
 
  • #9
66
0
I don't know what I was thinking, but yeah you use (final velocity)^2 = (initial velocity)^2 + 2*a*x and just substitute the stuff you know and solve for a.
 
  • #10
315
0
Does anyone know how to derive V^2=V0^2+2as

Ratch
 
  • #11
2,967
5
Take the velocity-time equation:
[tex]
v = v_{0} + a \, t
[/tex]
and the position time equation:
[tex]
x = v_{0} \, t + \frac{1}{2} \, a \, t^{2}
[/tex]
and eliminate time t.
 
  • #12
1,065
10
Does anyone know how to derive V^2=V0^2+2as

Ratch
Work energy theorem
KEv2-KEv0=mas
 

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