- #1
alexgraham
- 5
- 0
A car slows down from 23 m/s to rest in a distance of 85m. what was its acceleration, assumed constant?
a=Δv/Δt x=1/2at^2
i don't know where to start
a=Δv/Δt x=1/2at^2
i don't know where to start
Ratch said:Does anyone know how to derive V^2=V0^2+2as
Ratch
Motion is the change in position of an object over time.
Constant acceleration is when an object's velocity changes by the same amount over equal time intervals.
Acceleration is calculated by dividing the change in velocity by the change in time. The units for acceleration are meters per second squared (m/s²).
Speed is the rate at which an object is moving, while velocity is the rate at which an object is moving in a specific direction. Velocity takes into account both speed and direction.
According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. This means that as the force increases, the acceleration also increases, and as the mass increases, the acceleration decreases.