- #1

- 1

- 0

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter SarahV
- Start date

- #1

- 1

- 0

- #2

- 94

- 0

aceeleration=change in velocity/change in time so:

17-8/3=a

d=at

so d=a * 3 seconds

17-8/3=a

d=at

so d=a * 3 seconds

- #3

- 74

- 0

SarahV said:

Actually, d=at is incorrect.

The correct formula is [tex] v^2 - u^2 = 2as [/tex]. u is the initial velocity, in this case 8 m/s. We know [tex] a = 3 m/s^2 [/tex], therefore [tex] 17^2 - 8^2 = 2(3)s [/tex] and so [tex] s = (17^2 - 8^2)/6 [/tex] which turns out to be 37.5 m.

- #4

- 33

- 1

8+3a=17

a=3m/s^2

8*3+0.5*3*3^2=24+13.5=37.5m

a=3m/s^2

8*3+0.5*3*3^2=24+13.5=37.5m

- #5

- 5

- 0

Let me summarize the solution.

a=acceleration u=initial velocity v=final velocity

s=displacement t=time taken

a=(v-u)/t

a=(17.0-8.0)/3.0

a=3 m/(s^2)

s=((u+v)*t)/2

s=((8.0+17.0)*3.0)/2

s=37.5 m

Therefore, the acceleration is 3 m/(s^2) to his original direction and

the displacement he travelled is 37.5 m to his original direction.

a=acceleration u=initial velocity v=final velocity

s=displacement t=time taken

a=(v-u)/t

a=(17.0-8.0)/3.0

a=3 m/(s^2)

s=((u+v)*t)/2

s=((8.0+17.0)*3.0)/2

s=37.5 m

Therefore, the acceleration is 3 m/(s^2) to his original direction and

the displacement he travelled is 37.5 m to his original direction.

Last edited:

Share: