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Motion in 2 dimensions #2

  1. Jan 14, 2013 #1
    1. The problem statement, all variables and given/known data

    A particle leaves the origin with a velocity of 7.2 m/s in the positive y direction and moves in the xy plane with a constant acceleration of (3.0i - 2.0j) m/s2. At the instant the particle moves back across the x axis (y=0), what is the value of its x coordinate?

    2. Relevant equations

    vxf=vxi+axt
    xf=xi+.5(vxf+vxi)t
    xf=xi+vxit+.5axt2
    v2xf=v2xi+2ax(xf-xi)


    3. The attempt at a solution

    Are my x and y initial (0,0) because it says origin? Do I have to used to substitution as well?
     
  2. jcsd
  3. Jan 14, 2013 #2
    Starting at the origin does mean that xi=yi=0, yes.

    I'm not entirely sure what your second question means, but you should be able to formulate an expression for both the x and y position of the particle at any given time and then use substitution to find the answer.
     
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