# Motion in a Magnetic Field 1

1. Feb 23, 2013

### Gee Wiz

1. The problem statement, all variables and given/known data
A charged particle of mass m = 6X10-8 kg, moving with constant velocity in the y-direction enters a region containing a constant magnetic field B = 2.8T aligned with the positive z-axis as shown. The particle enters the region at (x,y) = (0.58 m, 0) and leaves the region at (x,y) = 0, 0.58 m a time t = 884 μs after it entered the region.

What is Fx, the x-component of the force on the particle at a time t1 = 294.7 μs after it entered the region containing the magnetic field.

2. Relevant equations
F=qv*B (i realize it is the cross product, but since they are perpendicular i can just multiply them since the angle is 90)
M*a=F
a=(v^2)/R

3. The attempt at a solution

Well i think i can find the total Force by just doing m*(v^2)/R. I got that F=.109N
I assume this question has to with trig, but its not popping out to me how to attack it.

Last edited: Feb 23, 2013
2. Feb 23, 2013

### Gee Wiz

I've also tried to take the velocity times the time to me give distance.

3. Feb 23, 2013

### Gee Wiz

Nevermind, figured it out.