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What is the radius of curvature for a proton moving in a magnetic field?
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[QUOTE="collinsmark, post: 4534601, member: 114325"] [b] You know that the center of the circle must be on the y-axis (if it wasn't then it wouldn't be perpendicular to the initial [I]V[/I]. You also have an idea of another slanted line that starts at the center of the circle and ends at the place where the proton exits, and that line is perpendicular to the final trajectory of the proton. Try to draw that wedge out. It will look like a section of pie or pizza. The bottom will be a [STRIKE]curved line[/STRIKE] [arc] indicating the path of the proton. Now, you already have [I]θ[/I] defined in your diagram, and you know that tan[I]θ[/I] = [I]V[/I][SUB]y[/SUB]/[I]V[/I][SUB]x[/SUB]. Now try to find/draw a similar triangle (in the wedge somewhere) that includes the circle's radius, [I]θ[/I], and [I]D[/I].[/b] [/QUOTE]
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Introductory Physics Homework Help
What is the radius of curvature for a proton moving in a magnetic field?
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