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Motion in a plane

  1. Apr 21, 2012 #1
    1. The problem statement, all variables and given/known data

    A projectile is fired with an initial speed of 30m/s at an angle of 60° above the horizontal.The object hits the ground 7.5s later.
    a)How much higher or lower is the launch point relative to the point where the projectile hits the ground?

    2. Relevant equations



    3. The attempt at a solution
    a)u(y)=30sin60,u(x)=30cos60
    v=u+at
    =30sin60-9.8*7.5
    =47.52 downwards
    tanθ=V(y)/V(x)
    =(-47.53/30cos60)
    =72.48° below the x-axis
    therefore,the launch point is 72.48°-60°=12.45° above relative to the point where the projectile hits the ground.
     
  2. jcsd
  3. Apr 21, 2012 #2
    The vertical displacement, y, is the point where the projectile hits the ground.
     
  4. Apr 21, 2012 #3
    Isn't the vertical displacement zero?
     
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