 #1
Fitz Watson
 7
 0
 Homework Statement:

A small particle slides from height H=45 cm as shown and
then loops inside the vertical loop of radius R from where a
section of angle = 60° has been removed. If R = (1/N)
meter, such that after losing contact at A and flying through
the air, the particle will reach at the topmost point B. Find
N. Neglect friction everywhere.
 Relevant Equations:

$$mg(h) = mg(h') + \frac{1}{2}mv^2$$
$$mg = \frac{mv^2}{r}$$
$$v^2 = g(0.9  3R)$$
The centripetal acceleration during the "flying through air" will be given by gravity
$$mg \cdot cos(\frac{\pi}{3}) = \frac{mv^2}{r}$$
$$R = \frac{1.8}{5}$$
But my book says $$ R = \frac{1}{5}$$