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Motion in one dimension help?

  1. Oct 17, 2012 #1
    An automobile which travels with the constant speed 20 m/s passes in a section in the moment t=0s and 5 seconds later in the same section passes another automobile which travles with the speed of 30 m/s in the same direction.a) Find when the second car meets the first one.
    My solution : x1=x2 20t=30(t-5) and here we find t=15 seconds.b) Whats the distance between the cars since the section until they meet? How to do this one? Just give me an idea..
     
  2. jcsd
  3. Oct 18, 2012 #2

    tiny-tim

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    Hi Elaia06! :smile:

    hmm :confused:

    ahh! o:), i think you mean …​
    your equations should be …
    x1 = 20t
    x2 = 30(t-5)
    x1 = x2 :wink:

    you already have t = 15,

    so x1 = x2 = … ? :smile:
     
  4. Oct 18, 2012 #3
    I did it this way, but my teacher said it was not correct o_O Now I logged in physicsforum and I see we have the same opinion :S Even the other students had done it this way.Whatever,thank you :)
     
  5. Oct 18, 2012 #4

    tiny-tim

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    Hi Elaia06! :smile:

    Please remember that I rewrote the question so that it fitted your solution!

    Perhaps the question means something different?
     
  6. Oct 18, 2012 #5
    So the distance question means " The two cars,since they pass the line have a distance.They keep this distance until they meet.Find the distance.This is basically what I did,found that distance.
     
  7. Oct 18, 2012 #6

    tiny-tim

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    sorry, but that doesn't make any sense :redface:

    (how can they keep the distance if the distance is getting smaller?)
     
  8. Oct 18, 2012 #7
    Thats what it says in my book,literally.I am not english and the book I work with is translated poorly ..Whatever,thank you anyway..
     
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