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Motion in one dimension help?

  1. Oct 17, 2012 #1
    A ball is released from the height 3 meters and after it hits the floor it reaches the height 2 meter. A) Whats the speed of the ball in the moment when it meets the ground?
    My answer : V^2-V0^2=2gs and here we find V=sqrt60.
    What is the speed of the ball in the moment it leaves the ground? V2^2-V^2=2gh2 so V2^2- sqrt60=2g*2 and here we find V2=10
    c) If the ball meets the ground for 0.02 seconds whats the direction and numerical value of the acceleration? The direction is upside down and a=(10-sqrt60)/0.02 ARE THESE CORRECT?
     
  2. jcsd
  3. Oct 18, 2012 #2

    tiny-tim

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    Hi Elaia06! :smile:

    (try using the X2 button just above the Reply box :wink:)
    fine :smile:
    no, that's a constant acceleration formula, so you can't use it "over the bounce" …

    try it with final speed 0 :wink:
     
  4. Oct 18, 2012 #3
    You mean I should correct the third question,not the second one? maybe you did a little mistake over there?
     
  5. Oct 18, 2012 #4

    tiny-tim

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    no i did mean the second question (What is the speed of the ball in the moment it leaves the ground?)
     
  6. Oct 18, 2012 #5
    I attached an image to the reply,it has the formulas for the non constant acceleration..but I dont have the time...
     

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