i have a quetion for you Dr., I know this is a simple problem but my physics book is not very clear on how to figure out this answer to the question. "A stone dropped from the top of a cliff. it hits the ground below after 3.25s. how high is the Cliff?" *to figure this out do you not use this equation? V^2 =Vo^2+ 2a(X-Xo)* a=9.8m/s, V=3.25s, initial V=0, X=?