A rock is dropped from rest into a well. The sound of the splash is heard 2.40 s after the rock is released from rest. a)How far below the top of the well is the surface of the water? The speed of sound in air (at the ambient temperature) is 336 m/s. (b) What If? If the travel time for the sound is neglected, what percentage error is introduced when the depth of the well is calculated? t=2.4 s V0=0 m/s v=336 m/s h= -(1/2)*9.8*(2.4-v/336)^2 m this the equation I have got. and when i solve it I get two values for h. but both of them have same signs. I am really lost...please help me out.