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Motion in Two Dimensions(particle acceleration equation to velocity & displacement)

  1. Oct 4, 2011 #1
    1. The problem statement, all variables and given/known data
    A particle moves with an acceleration a(t)=3at+2b with a=1m/s3 and b=1m/s2. Determine x(t) and v(t) such that v(1s)=4m/s and x(1s)=3m.

    This is how I tried to solve it:
    v(t)=∫(3at+2b)dt
    v(t)=3/2at2+2bt+const
    v(1s)=3/2m/s3(1s2)+2m/s2(1s)+const
    4m/s=7/2m/s+const
    const=1/2m/s

    v(t)=3/2at2+2bt+1/2m/s

    x(t)=∫(3/2at2+2bt+1/2m/s)dt
    x(t)=1/2at3+bt2+1/2m/s(t)+const
    x(1s)=1/2m/s3(1s3)+1m/s2(1s2)+1/2m/s(1s)+const
    3m=1/2m+1m+1/2m+const
    const=1m

    x(t)=1/2at3+bt2+1/2m/s(t)+1m

    Is this right, or where am I making errors?
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Oct 4, 2011 #2

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    Re: Motion in Two Dimensions(particle acceleration equation to velocity & displacemen

    Hello MelissaJL,

    Welcome to Physics Forums!
    'Looks correct to me. :approve:
     
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