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Motion of a ball

  • Thread starter lulu234
  • Start date
  • #1
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I have this question for my physics homework and I really don't understand it please help me! It's probably a really simple question but I just cant get my head round it!


1. a) at what time does the ball reach its maximum height?
b) calculate the maximum height that the ball reaches?
c) caculate the height from maximum to the ground?
d) Use your answers form c) and b) to caculate the height above the ground that the ball was thrown from?


2. Homework Equations [/b]



3. a) 1 seconds
b) d=s/t
 

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  • #2
tiny-tim
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hi lulu234! welcome to pf! :smile:
I have this question for my physics homework and I really don't understand it
the graph is velocity against time

you need to use it to draw a graph (or equation) of distance against time …

then you can answer the questions :wink:
 
  • #3
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how do I do that? :)
 
  • #4
tiny-tim
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how do I do that? :)
you have a graph of velocity against time

your lectures must have told you some information you can get from it :redface:
 
  • #5
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you have a graph of velocity against time

your lectures must have told you some information you can get from it :redface:
I don't know how to change velocity to distance :confused:
 
  • #6
berkeman
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I don't know how to change velocity to distance :confused:
That is hard to believe. We do not do your work for you here. You need to show some effort, or this thread will likely be deleted.
 
  • #7
berkeman
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That is hard to believe. We do not do your work for you here. You need to show some effort, or this thread will likely be deleted.
Sorry i'm 13 and my teacher hasn't shown me how?
 
  • #9
tiny-tim
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Sorry i'm 13 and my teacher hasn't shown me how?
has your teacher told you anything about the area under a graph? :smile:
 
  • #10
berkeman
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Sorry i'm 13 and my teacher hasn't shown me how?
Hang in there! Is the wikipedia page of help?
 
  • #11
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Yeah, thankyou I've got it now!:)
 

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