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Motion of a ball

  1. Sep 23, 2013 #1
    I have this question for my physics homework and I really don't understand it please help me! It's probably a really simple question but I just cant get my head round it!


    1. a) at what time does the ball reach its maximum height?
    b) calculate the maximum height that the ball reaches?
    c) caculate the height from maximum to the ground?
    d) Use your answers form c) and b) to caculate the height above the ground that the ball was thrown from?


    2. Relevant equations[/b]



    3. a) 1 seconds
    b) d=s/t
     

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  3. Sep 23, 2013 #2

    tiny-tim

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    hi lulu234! welcome to pf! :smile:
    the graph is velocity against time

    you need to use it to draw a graph (or equation) of distance against time …

    then you can answer the questions :wink:
     
  4. Sep 23, 2013 #3
    how do I do that? :)
     
  5. Sep 23, 2013 #4

    tiny-tim

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    you have a graph of velocity against time

    your lectures must have told you some information you can get from it :redface:
     
  6. Sep 23, 2013 #5
    I don't know how to change velocity to distance :confused:
     
  7. Sep 23, 2013 #6

    berkeman

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    That is hard to believe. We do not do your work for you here. You need to show some effort, or this thread will likely be deleted.
     
  8. Sep 23, 2013 #7

    berkeman

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  9. Sep 24, 2013 #8
    Sorry i'm 13 and my teacher hasn't shown me how?
     
  10. Sep 24, 2013 #9

    tiny-tim

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    has your teacher told you anything about the area under a graph? :smile:
     
  11. Sep 24, 2013 #10

    berkeman

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    Hang in there! Is the wikipedia page of help?
     
  12. Sep 24, 2013 #11
    Yeah, thankyou I've got it now!:)
     
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