# Motion of a particle

#### chart2006

1. Homework Statement

The two-dimensional motion of a particle is defined by the relationship $$r = \frac {1}{sin\theta - cos\theta}$$ and $$tan\theta = 1 + \frac {1}{t^2}$$, where $$r$$ and $$\theta$$ are expressed in meters and radians, respectively, and $$t$$ is expressed in seconds. Determine (a) the magnitudes of velocity and acceleration at any instant, (b) the radius of curvature of the path.

2. Homework Equations

$$r = \frac {1}{sin\theta - cos\theta}$$

$$tan\theta = 1 + \frac {1}{t^2}$$

3. The Attempt at a Solution

I've made a few attempts but they seem way more complicated than the problem should be I think. I'm assuming I need to solve $$tan\theta$$ for $$\theta$$. Once i've done that I figure I'd need to differentiate both $$r$$ and $$\theta$$ to find $$\dot{r}, \ddot{r}, \dot{\theta}, \ddot{\theta}$$.

I don't know if I'm on the correct route but any help would be appreciated. thanks!

Related Advanced Physics Homework Help News on Phys.org

#### gabbagabbahey

Homework Helper
Gold Member
I've made a few attempts but they seem way more complicated than the problem should be I think. I'm assuming I need to solve $$tan\theta$$ for $$\theta$$.
Tangent is not a one-to-one function, so that's a bad idea.

Instead, draw a picture! I think you can find expressions for $\sin\theta$ and $\cos\theta$ in terms of $t$ without actually solving for $\theta$ first.....think 'right triangle' ### Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving