Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Motion of a point charge in a magnetic field

  1. Feb 23, 2010 #1
    1. The problem statement, all variables and given/known data
    A proton with a speed 1.00x10^6 m/s enters a region with a uniform magnetic field of 0.800 T, and points into the page. The proton enters the region at an angle of 60º Find the exit angle and distance d.

    2. Relevant equations
    F=qvBsin(theta), F=qvxB

    3. The attempt at a solution
    I know that the charge of a proton is 1.6x10^-19C so I solved for the magnetic force.
    F=(1.6x10^-19C)(1.00x10^6m/s)(.800T)sin(60) =1.109x10^-13N
    I dont understand how I can get the exit angle now.
  2. jcsd
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?