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Homework Help: Motion of a point charge in a magnetic field

  1. Feb 24, 2010 #1
    1. The problem statement, all variables and given/known data
    A proton with a speed 1.00x10^6 m/s enters a region with a uniform magnetic field of 0.800 T, and points into the page. The proton enters the region at an angle of 60º Find the exit angle.

    2. Relevant equations
    F=qvBsin(theta), F=qvxB

    3. The attempt at a solution
    I know that the charge of a proton is 1.6x10^-19C so I solved for the magnetic force.
    F=(1.6x10^-19C)(1.00x10^6m/s)(.800T)sin(60) =1.109x10^-13N
    I dont understand how I can get the exit angle now.
     
  2. jcsd
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