- #1

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To what maximum height will the ball rise?

What horizontal distance will be traveled by the ball?

With what velocity (magnitude and direction) will it hit the ground?

I haven't started the second and third question yet. I wanted to use the equation y=1/2gt^2+Viy*t but I don't know what time or y is. Then I tried y=yo+tan(θ)x+g/(2v^2*cos(θ)^2)*x^2, but I don't have enough info to use it. Would I be wrong to move 10.07 to the origin, then use 0=1/2gt^2 to find maximum height?