I don't know a lot about physics so please excuse me. Let's say you have a marble rolling down a frictionless plane of an incline θ degrees from the horizontal. It begins at a height h(adsbygoogle = window.adsbygoogle || []).push({}); _{o}with an initial velocity of 0. I want to find the velocity of the marble at any height along the way. What I've done is below:

[tex]mgh=\frac{1}{2}mv^{2}\implies v=\sqrt{2gh}[/tex]

Since g is downward, I worked it out that the force in the direction of motion would be [itex]g\sin{\theta}[/itex]. Thus the velocity at any given height would be [itex]\sqrt{2gh\sin{\theta}}[/itex]. However, this doesn't account for the fact that the ball begins at rest. Is this incorrect or am I on the right track?

Thanks for your help.

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# Homework Help: Motion on an Incline

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