Motion on Incline Problem: Find 1st Mark in 2.5s

[Cole07]

problem: A ball is allowed to roll from rest down an inclined plane, and the distances are marked every 2.5s. if the second mark is made 1.5m from the starting point, where is the first mark?

where is the fourth mark?

well i made a velocity vs. t chart and the velocity of it is 0.6 then ifound the velocity of ech number on my graph but iwas told my answer was wrong. can you help me please.

 

[blackwizard]

well the ball is going to accelerate as it rolls down the plane. it sounds like ur assumin the velocity stays the same

 

[kyle8921]

Based on the given information, we can use the equation d=1/2at^2 to find the distance traveled by the ball in 2.5s. Since the ball starts from rest, its initial velocity (u) is 0. Therefore, we can rewrite the equation as d=ut+1/2at^2. Plugging in the values, we get d=0+(1/2)(9.8m/s^2)(2.5s)^2=30.625m.

This means that the first mark is 30.625m from the starting point.

To find the fourth mark, we can use the same equation with a different value for t. In this case, t=10s (since the fourth mark is made after 10s). So, d=0+(1/2)(9.8m/s^2)(10s)^2=245m.

Therefore, the fourth mark is 245m from the starting point.

It is important to note that this solution assumes that the ball is rolling without any external forces (such as friction) acting on it. If there are any other factors involved, the results may vary. It is also possible that there may be a mistake in the given information or in the calculations. I would suggest double-checking the values and equations used to ensure accuracy.