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Question: An object is dropped from a height of 50 m above ground from a helicopter. How long does the object take to reach the ground and what is its velocity on landing if the helicopter

(a) is at rest,

(b) is ascending with a velocity of 2 m/s,

(c) is descending with a velocity of 2 m/s and

(d) has just ascended to its maximum height and is about to descend at an acceleration 1 m/s2?

My answer:

(a) The initial velocity of the object dropped is u = 0 m/s because the helicopter is at rest. I can use v = u + at and v2 = u2 + 2as to find the answers.

(b) The initial velocity of the object dropped is u = -2 m/s because the helicopter is ascending with a velocity of 2 m/s.

(c) The initial velocity of the object dropped is u = 2 m/s because the helicopter is descending with a velocity of 2 m/s.

The steps to find the answers to (b) and (c) are the same as in (a).

(d) The initial velocity of the object dropped is also u = 0 m/s because the helicopter is just about to descend, no effect on the object. To find the answers, the steps are also the same as in part (a). And the answers to this part should be the same as in part (a) too.

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