(adsbygoogle = window.adsbygoogle || []).push({}); A hotel elevator ascends 230 m with a maximum speed of 5.8 m/s. Its acceleration and deceleration both have a magnitude of 1.0 m/s2.

(a) How far does the elevator move while accelerating to full speed from rest?

I got this part:

x = v/2a = 5.8/2(1) = 5.8^{2}/2 = 16.82 m

(b) How long does it take to make the complete trip from bottom to top?

I broke the problem up into three sections: the elevator going up (1.0 m/s^{2}), the elevator at rest (0), and the elevator coming back down (-1.0 m/s^{2}). I know that the elevator goes 230 m up and then 230 m down, but I cannot figure out which kinematic equation to use or if I need to use calculus (I have limited calculus knowledge).

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# Homework Help: Motion/Time Question

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