1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Motional EMF

  1. Nov 17, 2005 #1
    " A circular loop of wire 10 cm in diameter is placed with its normal making an angle of 30 degrees with the direction of a uniform 0.50T magnetic field. The loop is "wobbled" so that its normal rotates in a cone about the field direction at the constant rate of 100rev/min; the angle between the normal and the field direction (= 30 degrees) remains unchanged during the process. What emf appears in the loop?"

    Alright I know that I am supposed to use the equation:
    E(potential difference) = BDv
    With B as the magnetic field, D as the area with a magnetic field that is not equal to 0 and v is the velocity. The back of the book says that the emf is zero. Is this because the loop is not being displaced ( it is wobbling in the same spot?) so it's velocity is zero?
  2. jcsd
  3. Nov 18, 2005 #2

    Doc Al

    User Avatar

    Staff: Mentor

    That equation applies to a special case: That equation will calculate the motional EMF along a wire segment of length D that moves with speed v perpendicular to a magnetic field B.

    Rather than struggle to apply this equation, consider the more general Faraday's law. (Look it up if you need to.) What's the flux through the loop? Does the flux change?
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Motional EMF
  1. Amplitude of emf (Replies: 1)

  2. Induced Emf (Replies: 8)

  3. EMF Formula (Replies: 1)