Motor power in Kw

enginecadet88 · May 10, 2009

1. The problem statement, all variables and given/known data

Ok so i need to choose a motor that is capable of moving 15 tonnes (metric) over a distance of 16 m at 0.2 m/s.

So, im guessing i need to first find the force required to move this object which would be F=m*a. Is this right???

Now, what would be the equation to find the power required in Kw?

2. Relevant equations

3. The attempt at a solution

mgb_phys · May 10, 2009

No, f=ma is only the force needed to accelerate it upto 0.2m/s
The power is mainly to overcome friction.
You need to know what friction is involved, consider how hard it is to drag a 15tn rock over concrete compared to how much power you need to pull a 15tn boat.

enginecadet88 · May 10, 2009

Ill give some more background. The calculations i need really don't have to go into too much detail though.

This equation is for a crane trolley of 15 tonnes (metric) which moves along 2 beams. So, it is not a metal on metal contact. It will be a set of wheels or more accurately a rack and pinion set. Are there equations which do not take friction into account as i have been told by my lecturer that friction can be disregard.

mgb_phys · May 10, 2009

Neglecting friction it takes no power to keep the trolley moving at any speed.
To get it moving you have to put in energy = 1/2 m V^2, how quickly you do this (ie how long you take to accelerte it ) determines the power (power is energy/time)

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Motor power in Kw

enginecadet88

mgb_phys

enginecadet88

mgb_phys

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