Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Motor Sizing

  1. Nov 22, 2011 #1
    Hello,

    I need to size a motor for the following conditions,and I have managed to completly confuse myself:

    Motor will turn a hollow cylinder
    Cylinder mass = 10000kg
    radius = 0.759m
    acceleration = 0.25m/sec/sec
    Cylinder speed = 19 rpm

    I've been calulating the torque by:

    T = (I * a) where
    I = moment of inertia
    a = acceleration

    and the horsepower by

    HP = (n * T) / 5252 where
    n = cylinder RPM
    T = torque

    I can do all of this fine and the answer come out to around 2hp. However, I am confused about how adding a gearbox to this arrangement will affect the HP needed. I don't see anything in any of these formulas that take into account gear ratio. It seesm to me that if I were to add a significant gear reduction, I should be able to use a much smaller motor.

    Where am I going wrong?

    Thanks,

    Eric
     
  2. jcsd
  3. Nov 22, 2011 #2

    AlephZero

    User Avatar
    Science Advisor
    Homework Helper

    If you use a gearbox, you will get a different torque and a different RPM for the motor. It's a lot easier to make or buy a 2HP motor that runs at 1900 RPM than one that runs at 19 RPM, and the 1900 RPM motor only needs to produce 1/100 of the torque compared with the 19 RPM motor.

    But if the acceleration of the cylinder doesn't change, the power required to accelerate it doesn't change, so you still need a 2HP motor whatever speed it is designed to run at.
     
  4. Nov 23, 2011 #3
    Because using a gearbox will increase the torque and decrease the speed (or vice-versa) proportionally, the power output required from the motor would be equal (ignoring the slight amount of friction in the gearbox).
     
  5. Nov 25, 2011 #4
    You have to take into account inertia ratio hollow cylinder and motor armature inertia it should be less than 3 , if other wise you have to go for higher power motor to reduce the shock
    Let Imr be the moment of inertia reflected at motor shaft, Ic be the moment of Inertia of cylinder, N1 be motor speed and N2 be the cylinder speed

    then Imr = Ic x (N2)^2/(N1)^2 it is the moment of Inertia reflected at the motor shaft and it should less than 3
     
    Last edited: Nov 25, 2011
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Motor Sizing
  1. Sizing a dc motor (Replies: 1)

Loading...