- #1
ncr7
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Looking for a motor to turn a large cylinder.
Say if I have a cylinder of radius 1007.54mm and mass of 2 tons, I would have a moment of innertia of 1.027x10^3 kg-m^2
This is from the general cylinder inertial equation,
I = .5*m*r^2
The torque necessary to bring this to 30 deg/ 5 min is
W= [tex]\varpi[/tex]0 rad/sec + .5*[tex]\alpha[/tex]*(5 min/60 sec)^2
W = 30 deg*(3.14 rad/180 deg)*2/(.00694 sec^2)
W = 6.06x10^(-5) rad/sec^2
Torque is then,
T = 1.027x10^3*6.06x10^-5 rad/sec^2
T = .06224 N-m
Correct?
and if this is so if I had a motor with a minimum torque of .06224 N-m?
I think this is correct but thought I'd have someone run over calculations and see if I am looking for a motor the right way. Thank you!
Say if I have a cylinder of radius 1007.54mm and mass of 2 tons, I would have a moment of innertia of 1.027x10^3 kg-m^2
This is from the general cylinder inertial equation,
I = .5*m*r^2
The torque necessary to bring this to 30 deg/ 5 min is
W= [tex]\varpi[/tex]0 rad/sec + .5*[tex]\alpha[/tex]*(5 min/60 sec)^2
W = 30 deg*(3.14 rad/180 deg)*2/(.00694 sec^2)
W = 6.06x10^(-5) rad/sec^2
Torque is then,
T = 1.027x10^3*6.06x10^-5 rad/sec^2
T = .06224 N-m
Correct?
and if this is so if I had a motor with a minimum torque of .06224 N-m?
I think this is correct but thought I'd have someone run over calculations and see if I am looking for a motor the right way. Thank you!
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