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## Homework Statement

From a height

*40 meters*up, one throw a ball with the velocity of 20 m/s. The elevation is 0°. How far does the ball come?

v

_{o}= 20 m/s

x = 40 meters

α = 0°

(g=9.82)

## Homework Equations

y = v

_{0}× t × sinα - (9.82×t

^{2})/2

x= v

_{0}×t×cosα

## The Attempt at a Solution

I put what I know in there

40 = 20×t×sin0° - (9.82×t

^{2})/2

=>

80/9.82 = t

^{2}

=>

√(80/9.82) = t = 2.85 s (Is that right?)

Then I put all I know in the other formula to get x:

x= v

_{0}×t×cosα

x = 20×2.85×cos0°

**x=57 meters**(Doesn't that feel a little too short?)

I've no answer to this question and I would be really glad if someone could confirm that this is correct calculated :)

Edit: There's no air resistance