(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

From a height40 metersup, one throw a ball with the velocity of 20 m/s. The elevation is 0°. How far does the ball come?

v_{o}= 20 m/s

x = 40 meters

α = 0°

(g=9.82)

2. Relevant equations

y = v_{0}× t × sinα - (9.82×t^{2})/2

x= v_{0}×t×cosα

3. The attempt at a solution

I put what I know in there

40 = 20×t×sin0° - (9.82×t^{2})/2

=>

80/9.82 = t^{2}

=>

√(80/9.82) = t = 2.85 s (Is that right?)

Then I put all I know in the other formula to get x:

x= v_{0}×t×cosα

x = 20×2.85×cos0°

x=57 meters

(Doesn't that feel a little too short?)

I've no answer to this question and I would be really glad if someone could confirm that this is correct calculated :)

Edit: There's no air resistance

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# Homework Help: Movement in x,y line

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