NOTE: This is no homework, just me having fun with physics, maths, logics etc. Do not take this problem as priority, there are surely more serious and urgent problems out there!(adsbygoogle = window.adsbygoogle || []).push({});

1. The problem statement, all variables and given/known data

A passenger standing beside the railway noticed that the first wagon of the electric train, decelerating linearly, passed beside him after 4 s, and the second wagon after 5 s. The first wagon stopped at 75 m in front of the passenger. Calculate the acceleration of the train.

t1 = 4 s

t2 = 5 s

s1 = 75 m

2. Relevant equations

s = v0*t - a*t^2/2

v = v0 - at

3. The attempt at a solution

Assuming the second wagon was the last and that it stopped at the same time as the first and that both are of same length, it is to say that the length of both wagons is 75 m. This also means it took the train 75 m and 9 total seconds to decelerate to 0. Now I wrote:

75 = 9*v0 - (81*a)/2

Since we don't know v0, we insert it from the following equation:

0 = v0 - 9a

v0 = 9a

--> 75 = 9*9a - (81*a)/2

75 = 81a - (81a)/2

after solving:a = -1.85 m/s^2

Then we find v0:

0 = v0 - 16.65

v0 = 16.61 m/s

As I do not have the solutions and the page from where I downloaded the assignments (in Croatian) didn't even offer them, I'm just asking from your opinion and critics and eventually the right solution.

I also tried this by not including v0 and using a different concept, however without it even more weird solutions came up. Any help is appreciated.

Thanks in advance.

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# Homework Help: Moving train problem

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