hello(adsbygoogle = window.adsbygoogle || []).push({});

In this MTW Ex 21.16, MTW refers to box 14.5 in which the Riemann curvature scalar contains a second derivative of the scale factor a for the same Friedmann metric.

Now using the equation suggested by MTW, i.e. eq 21.77, the value of tr(K)^{2}- tr(K^{2}) would be zero since K is multiple of the unit tensor.

This is said, what remains of Eq 21.77 is simply :

-G^{0}_{0}= 1/2R^{0}_{0}

but this would not yield the equation to be proved since we still have a second derivative of a.

I'm confused.

Note: In Landau's section 107 however, the value of the G^{0}_{0}found will give the equation to be proved despite the difference of the values of the curvature tensors.

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# MTW Exercise 21.16

Can you offer guidance or do you also need help?

Draft saved
Draft deleted

Loading...

Similar Threads - Exercise | Date |
---|---|

A Simple 1D kinematic exercises with metric tensor | May 24, 2017 |

B An exercise for students | Apr 1, 2017 |

I Are many exercises in Schutz just too hard? | Oct 4, 2016 |

MTW Exercise 25.5 b) - killing vectors | Nov 30, 2013 |

Exercise 2.5 in Misner, Thorne and Wheeler | Jul 4, 2013 |

**Physics Forums - The Fusion of Science and Community**